40 lines
1.6 KiB
MiniZinc
40 lines
1.6 KiB
MiniZinc
int: h; set of int: H = 1..h; % 板高度
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int: w; set of int: W = 1..w; % 板宽度
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array[H,W] of -1..5: b; % 板
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int: E = -1; % 空白格
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set of int: N = 0..4; % 填充并含有数字的网格
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int: F = 5; % 填充但不含有数字的网格
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% 位置 (i1,j1) 对位置 (i2,j2) 可见
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test visible(int: i1, int: j1, int: i2, int: j2) =
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((i1 == i2) /\ forall(j in min(j1,j2)..max(j1,j2))(b[i1,j] == E))
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\/ ((j1 == j2) /\ forall(i in min(i1,i2)..max(i1,i2))(b[i,j1] == E));
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array[H,W] of var bool: l; % is there a light
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% 填充的网格没有灯泡
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constraint forall(i in H, j in W where b[i,j] != E)(l[i,j] == false);
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% lights next to filled numbered square agree
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constraint forall(i in H, j in W where b[i,j] in N)(
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bool_sum_eq([ l[i1,j1] | i1 in i-1..i+1, j1 in j-1..j+1 where
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abs(i1 - i) + abs(j1 - j) == 1 /\
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i1 in H /\ j1 in W ], b[i,j]));
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% 每个空白网格是被照亮的
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constraint forall(i in H, j in W where b[i,j] == E)(
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exists(j1 in W where visible(i,j,i,j1))(l[i,j1]) \/
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exists(i1 in H where visible(i,j,i1,j))(l[i1,j])
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);
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% 任何两个灯泡看不到彼此
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constraint forall(i1,i2 in H, j1,j2 in W where
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(i1 != i2 \/ j1 != j2) /\ b[i1,j1] == E
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/\ b[i2,j2] == E /\ visible(i1,j1,i2,j2))(
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not l[i1,j1] \/ not l[i2,j2]
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);
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solve satisfy;
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output [ if b[i,j] != E then show(b[i,j])
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else if fix(l[i,j]) then "L" else "." endif
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endif ++ if j == w then "\n" else " " endif |
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i in H, j in W];
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