61 lines
3.0 KiB
MiniZinc
61 lines
3.0 KiB
MiniZinc
include "fzn_mdd.mzn";
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include "fzn_mdd_reif.mzn";
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/** @group globals.extensional
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Requires that \a x defines a path from root to true node T through the (deterministic) MDD defined by
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\a N is the number of nodes, the root node is node 1
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\a level is the level of each node, the root is level 1, T is level \a length(x)+1
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\a E is the number of edges
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\a from is the leaving node (1..\a N)for each edge
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\a label is the set of values of the \a x variable for each edge
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\a to is the entering node for each edge, where 0 = T node
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The MDD must be deterministic, i.e., there cannot be two edges
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with the same label leaving the same node.
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*/
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predicate mdd(array[int] of var int: x, % variables constrained by MDD
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int: N, % number of nodes root is node 1
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array[int] of int: level, % level of each node root is level 1, T is level length(x)+1
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int: E, % number of edges
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array[int] of int: from, % edge leaving node 1..N
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array[int] of set of int: label, % possible values of variable
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array[int] of int: to % edge entering node 0..N where 0 = T node
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) =
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let { set of int: NODE = 1..N;
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set of int: EDGE = 1..E;
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int: L = length(x);
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array[0..N] of int: levele = array1d(0..N,[L+1]++level); } in
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assert(index_set(level) = NODE,
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"mdd: third argument must be of length N = \(N)") /\
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assert(index_set(from) = EDGE,
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"mdd: 5th argument must be of length E = \(E)") /\
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assert(index_set(to) = EDGE,
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"mdd: 7th argument must be of length E = \(E)") /\
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forall(e in EDGE)(assert(from[e] in NODE,
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"mdd: from[\(e)] must be in \(NODE)")) /\
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forall(e in EDGE)(assert(to[e] in 0..N,
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"mdd: to[\(e)] must be in 0..\(N)")) /\
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forall(e in EDGE)(assert(level[from[e]]+1 = levele[to[e]],
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"mdd level of from[\(e)] = \(level[from[e]])" ++
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"must be 1 less than level of to[\(e)] = \(levele[to[e]])")) /\
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forall(e1,e2 in EDGE where e1 < e2 /\ from[e1] = from[e2])
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(assert(label[e1] intersect label[e2] = {},
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"mdd: Two edges \(e1) and \(e2) leaving node \(from[e1]) with overlapping labels")) /\
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fzn_mdd(x, N, level, E, from, label, to);
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% Example consider an MDD over 3 variables
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% 5 nodes and 12 edges
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% level 1 root = 1
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% level 2 2 3
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% level 3 4 5
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% level 4 T
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% with edges (from,label,to) given by
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% (1,1,2), (1,2,3), (1,3,2)
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% (2,2,4), (2,3,5)
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% (3,3,4), (3,2,5)
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% (4,1,0), (4,5,0)
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% (5,2,0), (5,4,0), (5,6,0)
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% this is defined by the call
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% mdd([x1,x2,x3],5,[1,2,2,3,3],12,[1,1,1,2,2,3,3,4,4,5,5,5],[1,3,2,2,3,3,2,1,5,2,4,6],[2,2,3,4,5,4,5,0,0,0,0,0])
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