81 lines
1.8 KiB
MiniZinc
81 lines
1.8 KiB
MiniZinc
% RUNS ON mzn20_fd
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% RUNS ON mzn-fzn_fd
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% RUNS ON mzn20_fd_linear
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% RUNS ON mzn20_mip
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% Regression test for a bug in mzn2fzn 1.2. The optimisation pass was leaving
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% dangling references to variables it had "eliminated". The symptom was the
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% following error from the FlatZinc interpreter:
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%
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% subsets_100.fzn:413:
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% symbol error: `INT____407' undeclared
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%
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% (This model is from the original bug report.)
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% Subsets 100 puzzle in MiniZinc.
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%
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% From rec.puzzle FAQ
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% http://brainyplanet.com/index.php/Subsets?PHPSESSID=051ae1e2b6df794a5a08fc7b5ecf8028
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% """
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% Out of the set of integers 1,...,100 you are given ten different integers.
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% From this set, A, of ten integers you can always find two disjoint non-empty
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% subsets, S & T, such that the sum of elements in S equals the sum of elements
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% in T. Note: S union T need not be all ten elements of A. Prove this.
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% """
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%
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% This MiniZinc model was created by Hakan Kjellerstrand, hakank@bonetmail.com
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% See also my MiniZinc page: http://www.hakank.org/minizinc
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%
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include "globals.mzn";
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int: n = 100;
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int: m = 10;
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var set of 1..n: s;
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var set of 1..n: t;
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var int: s_total;
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var int: t_total;
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%
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% sums the integer in set ss
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%
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predicate sum_set(var set of int: ss, var int: total) =
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let {
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int: m = card(ub(ss)),
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array[1..m] of var 0..1: tmp
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}
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in
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forall(i in 1..m) (
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i in ss <-> tmp[i] = 1
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)
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/\
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total = sum(i in 1..m) (i*tmp[i])
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;
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solve :: set_search([s,t],
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input_order, indomain_min, complete) satisfy;
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constraint
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card(s union t) <= m
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/\
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card(s union t) > 0
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/\
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disjoint(s, t)
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/\
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sum_set(s, s_total)
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/\
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sum_set(t, t_total)
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/\
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s_total = t_total
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% /\
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% t_total = n
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;
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output [
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"s: ", show(s), "\n",
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"t: ", show(t), "\n",
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"s_total: ", show(s_total), "\n",
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"t_total: ", show(t_total), "\n",
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];
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